Electronics · AC and power / Principles and inquiry
AC and RMS voltage experiment guide
Compare mean heating under AC and DC to find the RMS voltage.
How does it work?
For a sine wave RMS is peak/√2, and mean power is Vrms²/R.
Key relationship
Vrms = V₀/√2 · Pavg = V₀²/(2R)
Try this investigation
- Compare mean heating under AC and DC to find the RMS voltage.
- Run and record each of the three baseline presets.
- Compare the changed variable and its result with the baseline records.
Interpreting your results
What is the mean power of a 6 V peak sine wave across 20 Ω?
0.9 W
Assumptions and limitations
The load is an ideal resistor, so current and voltage have no phase difference. Experiment on screen; do not reproduce this with real power supplies, outlets or high voltage.