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Earth Science · Atmosphere · Weather

Rising air, cooling, and clouds

If the air rises and expands, it can cool, and if it reaches its dew point, condensation may begin. The difference between the temperature and the dew point is an indicator of the base of clouds.

Related experiment: Rising air and clouds →
Rising air and clouds
Rising air and clouds: simulation view →

Meaning and mechanism

As the air mass rises, it expands due to a decrease in surrounding pressure. In cases where heat exchange with the outside is a small approximation of insulation, the temperature decreases as it expands.

When the air temperature approaches the dew point, the relative humidity increases. This difference in temperature decrease rate compared to when the air is dry is due to the release of latent heat following saturation.

Relationships and conditions

Before saturation, the simulation assumes that air temperature falls by 10 °C/km and dew point by 2 °C/km. It approximates the condensation height as (T−Td)/8 km because the difference between the two decreases at that rate.

The wettability and thermal resistance of a surface actually change depending on temperature, pressure, and humidity levels. This simple model does not predict the height or rainfall of all clouds.

What to observe in the simulation

Before condensation, the model reduces air temperature by 10 °C per km and dew point by 2 °C per km. After condensation, it uses an air-temperature decrease of 5 °C per km.

It is an interval approximation that sets the dry, dew point, and wet lapse rates as constants of 10, 2, and 5 ℃/km, respectively. The lapse rate changes due to mixing, radiation, and atmospheric pressure are omitted. Stability/unstability is a buoyancy judgment that compares the surroundings and temperature at a given height, and is not the stability of the entire atmosphere or the actual cloud and precipitation forecast.

Key relationships and symbols

Condensation altitude = (T−Td)/8 km

Symbols and units used in the formulas
SymbolMeaningUnit
T, TdInitial air temperature and dew point°C
Lapse rateRate of temperature change with height°C/km

Worked example

What is the temperature of the air parcel at the condensation altitude of 1.5 km?

(25−13)/(10−2)=1.5 km. Before condensation, it cools by 10 ℃/km, so 25−10×1.5=10 ℃.

Common misconceptions

  • It is not possible to explain the phenomenon of air rising and cooling solely by describing it as a process where higher locations “steal” heat by cooling the air.

Explore this concept through experiments

References

BCcampus · Physical Geology (English)