itslabtime.com

Life Science · Cell · Matter Transfer

Cell surface-area-to-volume ratio

As cells grow larger, their volume increases faster than their surface area. The area for exchanging materials and the distance to the inside are subject to different constraints.

Related experiment: Cell size and material exchange →
Cell size and material exchange
Cell size and material exchange: simulation view →

Meaning and mechanism

The surface of the cell membrane is a boundary for exchanging with the outside, and the internal volume is a space that needs to be supplied. The two quantities do not increase at the same rate according to size.

If you increase the length of one side of a cube by a factor of two, its surface area becomes four times larger, and its volume becomes eight times larger. The surface area corresponding to one unit of volume is halved.

Relationships and conditions

The surface area to volume ratio [SA/V] of a cube with side length a is 6/a. The representative distance for one-directional diffusion is √(2Dt)), so the time required to move the same distance doubled is four times as long.

Real cells utilize compartmentalization, membrane wrinkles, and active transport and internal flow. It is not possible to determine the maximum size of all cells using only simple size models.

What to observe in the simulation

Smaller cubes have a larger surface area/volume and reach a larger volume ratio with the same depth of diffusion. The penetration rate is 1−((a−2d)/a)³ and is 100% if a≤2d.

It is a model that penetrates an agar cube uniformly from six sides with a constant diffusion coefficient. A sharp boundary and d=√(2Dt) are approximate. The actual concentration distribution, cell membrane transport, metabolism, and spherical cell geometry are omitted. The color area ratio of the cross section and the three-dimensional penetration volume ratio are different.

Key relationships and symbols

d = √(2Dt) · SA/V = 6/a

Symbols and units used in the formulas
SymbolMeaningUnit
aSide length of the model cellm
DDiffusion coefficientm²/s
SA/VSurface-area-to-volume ratiom⁻¹

Worked example

What is the penetration volume ratio when a=2 cm and penetration depth d=0.5 cm?

The remaining central side is 2−2×0.5=1 cm. The uninfiltrated volume ratio is 1³/2³=1/8, so the infiltration ratio is 87.5%.

Common misconceptions

  • The surface area does not necessarily become better than the volume in terms of exchange conditions simply because it has increased.

Explore this concept through experiments

References

OpenStax · Biology 2e (English)